{"id":9667,"date":"2024-01-18T02:10:38","date_gmt":"2024-01-17T19:10:38","guid":{"rendered":"https:\/\/157.\/?p=9667"},"modified":"2024-04-24T22:29:42","modified_gmt":"2024-04-24T15:29:42","slug":"keo-3-4-la-sao","status":"publish","type":"post","link":"https:\/\/157.\/keo-3-4-la-sao\/","title":{"rendered":"K\u00e8o 3\/4 l\u00e0 g\u00ec – Kinh nghi\u1ec7m b\u1eaft k\u00e8o chu\u1ea9n x\u00e1c nh\u1ea5t"},"content":{"rendered":"

K\u00e8o 3\/4 l\u00e0 g\u00ec<\/b>? C\u00e1ch b\u1eaft c\u01b0\u1ee3c v\u00e0 t\u00ednh ti\u1ec1n c\u1ee7a k\u00e8o 3\/4 c\u00f3 g\u00ec kh\u00e1c so v\u1edbi k\u00e8o 1\/2 v\u00e0 k\u00e8o 1 tr\u00e1i? T\u1ea1i sao khi nh\u00ecn tr\u00ean b\u1ea3ng k\u00e8o ch\u00fang ta l\u1ea1i kh\u00f4ng t\u00ecm th\u1ea5y bao gi\u1edd c\u1ea3? H\u00e3y c\u00f9ng v\u1edbi <\/span>trang c\u00e1 c\u01b0\u1ee3c Kubet88<\/a><\/b> gi\u1ea3i \u0111\u00e1p c\u00e1c th\u1eafc m\u1eafc tr\u00ean; c\u0169ng nh\u01b0 t\u00ecm hi\u1ec3u chi ti\u1ebft h\u01a1n v\u1ec1 k\u00e8o n\u00e0y ngay trong b\u00e0i vi\u1ebft n\u00e0y nh\u00e9.<\/span><\/p>\n

T\u00ecm hi\u1ec3u k\u00e8o 3\/4 l\u00e0 g\u00ec?<\/b><\/h2>\n

\u0110\u00e2y l\u00e0 m\u1ed9t k\u00e8o ch\u1ea5p ch\u00e2u \u00c1, trong \u0111\u00f3 \u0111\u1ed9i m\u1ea1nh h\u01a1n s\u1ebd \u1edf c\u1eeda tr\u00ean; v\u00e0 c\u1ea7n ph\u1ea3i ch\u1ea5p 3\/4 tr\u00e1i cho \u0111\u1ed9i c\u1eeda d\u01b0\u1edbi (\u0111\u1ed9i y\u1ebfu h\u01a1n). K\u00e8o ch\u1ea5p 3\/4 n\u1eb1m gi\u1eefa k\u00e8o ch\u1ea5p 1\/2 v\u00e0 k\u00e8o 1 tr\u00e1i; c\u00f2n c\u00f3 th\u1ec3 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 k\u00e8o 0.75 hay l\u00e0 k\u00e8o ch\u1ea5p n\u1eeda m\u1ed9t, th\u1ec3 hi\u1ec7n n\u1eb1m gi\u1eefa “m\u1ed9t n\u1eeda” v\u00e0 “m\u1ed9t”.<\/span><\/p>\n

\"T\u00ecm
T\u00ecm hi\u1ec3u k\u00e8o 3\/4 l\u00e0 sao?<\/figcaption><\/figure>\n

K\u00e8o 3\/4 c\u0169ng th\u1ec3 hi\u1ec7n r\u1eb1ng s\u1ef1 ch\u00eanh l\u1ec7ch tr\u00ecnh \u0111\u1ed9 c\u1ee7a 2 \u0111\u1ed9i b\u00f3ng l\u00e0 r\u1ea5t r\u00f5 r\u00e0ng. Khi c\u00f3 m\u1ed9t \u0111\u1ed9i ch\u1ea5p cho \u0111\u1ed9i c\u00f2n l\u1ea1i 3\/4 tr\u00e1i. Ngh\u0129a l\u00e0 \u0111\u1ec3 th\u1eafng k\u00e8o th\u00ec t\u1ef7 s\u1ed1 s\u1ebd c\u1ea7n ph\u1ea3i c\u00f3 c\u00e1ch bi\u1ec7t 2 b\u00e0n tr\u1edf l\u00ean. \u0110i\u1ec1u n\u00e0y nh\u1eb1m tr\u00e1nh tr\u01b0\u1eddng h\u1ee3p c\u00e1c c\u01b0\u1ee3c th\u1ee7 b\u1eaft k\u00e8o l\u1ec7ch v\u1ec1 \u0111\u1ed9i c\u1eeda tr\u00ean; m\u1ea5t c\u00e2n b\u1eb1ng v\u1ec1 cu\u1ed9c ch\u01a1i m\u00e0 vi\u1ec7c c\u00e1 \u0111\u1ed9 kh\u00f4ng c\u00f2n th\u00fa v\u1ecb n\u1eefa.<\/span><\/p>\n

Ngo\u00e0i ra, c\u01b0\u1ee3c th\u1ee7 c\u00f3 th\u1ec3 nh\u00ecn v\u00e0o k\u00e8o n\u00e0y \u0111\u1ec3 b\u1eaft c\u01b0\u1ee3c sang k\u00e8o ch\u00e2u \u00c2u. \u0110\u1ed1i v\u1edbi c\u01b0\u1ee3c th\u1ee7 l\u00e2u n\u0103m th\u00ec nh\u00ecn v\u00e0o ch\u1ec9 s\u1ed1 k\u00e8o ch\u1ea5p ch\u00e2u \u00c1 \u0111\u1ec3 b\u1eaft k\u00e8o ch\u00e2u \u00c2u l\u00e0 m\u1ed9t \u0111i\u1ec1u h\u1ebft s\u1ee9c b\u00ecnh th\u01b0\u1eddng. B\u1edfi trong k\u00e8o ch\u00e2u \u00c2u ch\u00fang ta ch\u1ec9 b\u1eaft th\u1eafng – thua – h\u00f2a m\u00e0 th\u00f4i.<\/span><\/p>\n

K\u00e8o 3\/4 hi\u1ec3n th\u1ecb tr\u00ean b\u1ea3ng k\u00e8o nh\u01b0 n\u00e0o?<\/b><\/h2>\n

Ch\u1eafc h\u1eb3n, khi anh em t\u00ecm k\u00e8o 0.75 \u1edf tr\u00ean b\u1ea3ng k\u00e8o \u0111\u1ec1u kh\u00f4ng th\u1ea5y \u0111\u00fang kh\u00f4ng n\u00e0o?<\/span> \u0110\u00f3 ch\u00ednh l\u00e0 b\u1edfi v\u00ec ch\u00fang \u0111\u01b0\u1ee3c hi\u1ec3n th\u1ecb \u1edf d\u1ea1ng th\u1eadp ph\u00e2n (0.75); ho\u1eb7c l\u00e0 hi\u1ec3n th\u1ecb k\u00e8o tr\u01b0\u1edbc v\u00e0 sau c\u1ee7a n\u00f3 (0.5\/1 ho\u1eb7c 0.5-1). Nguy\u00ean nh\u00e2n c\u1ee7a vi\u1ec7c n\u00e0y v\u00ec 0.75 tr\u00e1i l\u00e0 con s\u1ed1 \u1edf gi\u1eefa 0.5 tr\u00e1i v\u00e0 1 tr\u00e1i.<\/span><\/p>\n

\u0110\u1ed1i v\u1edbi c\u01b0\u1ee3c th\u1ee7 l\u00e2u n\u0103m th\u00ec h\u1ecd c\u00f3 th\u1ec3 soi k\u00e8o ch\u00ednh x\u00e1c v\u00e0 k\u1ef9 l\u01b0\u1ee1ng. Tuy nhi\u00ean n\u1ebfu nh\u01b0 b\u1ea1n l\u00e0 m\u1ed9t t\u00e2n binh th\u00ec c\u1ea7n \u0111\u1eb7c bi\u1ec7t ch\u00fa \u00fd. R\u1ea5t nhi\u1ec1u anh em \u0111\u00e3 b\u1ecb nh\u1ea7m l\u1eabn k\u00e8o 3\/4 v\u00e0 k\u00e8o 1 tr\u00e1i ho\u1eb7c k\u00e8o 1.75 tr\u00e1i (k\u00e8o 1 3\/4) hay 2.75 tr\u00e1i (k\u00e8o 2 3\/4).<\/span><\/p>\n

\"K\u00e8o
K\u00e8o 3\/4 hi\u1ec3n th\u1ecb tr\u00ean b\u1ea3ng k\u00e8o nh\u01b0 n\u00e0o?<\/figcaption><\/figure>\n

C\u00e1ch ch\u01a1i c\u1ee7a k\u00e8o \u00be nh\u01b0 th\u1ebf n\u00e0o?<\/b><\/h2>\n

N\u1ebfu anh em \u0111\u00e3 t\u1eebng th\u1eed c\u01b0\u1ee3c k\u00e8o 3\/4; ch\u1eafc h\u1eb3n s\u1ebd g\u1eb7p tr\u01b0\u1eddng h\u1ee3p \u0103n n\u1eeda ti\u1ec1n\/m\u1ea5t n\u1eeda ti\u1ec1n ho\u1eb7c \u0103n c\u1ea3\/thua c\u1ea3. Th\u1ef1c t\u1ebf th\u00ec \u0111i\u1ec1u n\u00e0y x\u1ea3y ra b\u1edfi lu\u1eadt ch\u01a1i c\u1ee7a k\u00e8o c\u01b0\u1ee3c. V\u1eady c\u1ee5 th\u1ec3 v\u1ec1 c\u00e1c tr\u01b0\u1eddng h\u1ee3p b\u1eaft c\u01b0\u1ee3c:<\/span><\/p>\n